Question

Se x (1-x) = 1/4 então?

Answer 1

-x² +x -1/4 = 0 * (-4)

4x² -4x +1 = 0

$\boxed{\mathsf{\Delta=b^2-4ac}}$

16 -4 * 1 * 4

0

$\boxed{\mathsf{x=\frac{-b\pm\sqrt{\Delta}}{2a}}}}$

4 ± 0 /8

4/8

x = 1/2

Answer 2

x( 1+x) = 1/4

x= $x^{2}$ = 1/4

-$x^{2}$ + x _ 1/4 = 0

-4$x^{2}$ + 4x - 1 = 0

Agora tira o Bhaskara

Δ= b² - 4ac

Δ= 16 - 4 (-4). (-1)

Δ= 16-16

Δ= 0

x1 0 x2 = -4/-8 = 1/2

S { 1/2}

Espero ter ajudado!