Question

Me ajudem pfv, Equação exponencial :

Answer 1

$(\frac{3}{2})^{2x}=u$

2u² -5u +3 = 0

$\boxed{\mathsf{\Delta=b^2-4ac}}$

(-5)² -4 * 2 * 3

25 -24

1

$\boxed{\mathsf{u=\frac{-b\pm\sqrt{\Delta}}{2a}}}}$

[ -(-5) ± √1 ]/(2 * 2)

(5 ± 1)/4

u' = 3/2

$(\frac{3}{2})^{2x}=(\frac{3}{2})$

x' = 1/2

u'' = 1

$(\frac{3}{2})^{2x}=1$

x'' = 0

{1/2 , 0}