Question

calcular o limite abaixo

lim 8+x³/4-x²
x->-2

Answer 1

$\lim_{x \to -2} \frac{8+x^3}{4-x^2} =\\ \\ \lim_{x \to -2} \frac{(x+2)(x^2-2x+4)}{(2+x)(2-x)} =\\ \\ \lim_{x \to -2} \frac{x^2-2x+4}{2-x} = \frac{12}{4}=3$