Question

calcular a soma da dos numeros pares compreendidos entre 1 e 101

Answer 1

2+4+6+8+10+12+14+16+18+20+22+24+26+28+30+32+34+36+38+40+42+44+46+48+50+52+54+56+58+60+62+64+66+68+70+72+74+76+78+80+82+84+86+88+90+92+94+96+98+100=


R: 2.550

Answer 2

{1 [2...4...6...8... ... 100] 101}

an = 100   a1 = 2     r= 2    n=?

an = a1 + (n-1) r

100 = 2 + (n - 1) 2

100 = 2 + 2n - 2

100 -2+2 = 2n

100 = 2n

n = 50

s =[ (a1+an)/2 ] n

s = [(2+100)/2]50 =

s = 2250 --->  resposta