Question

Encontre o 6º termo da PG (27,9,3,...)

Answer 1

$n = 6\\\\ a_{1} = 27\\\\ a_{2} = 9\\\\ a_{3} = 3\\\\ a_{6} = a_{1}.q^{n - 1}\\\\ q = \frac{9}{27} = \frac{3^{:3} }{9^{:3} } = \frac{1}{3}\\\\ a_{6} = 27.(\frac{1}{3} )^{6 - 1}\\\\ a_{6} = 27.(\frac{1}{3})^{5}\\\\ a_{6} = 27.\frac{1}{243}\\\\ a_{6} = \frac{27^{:27} }{243^{:27} } = \frac{1}{9}$

Espero ter ajudado!

Answer 2

Boa noite!

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Dados;

A1 → 27

N → 6

An → ?

Q → 9/27 → 3/9 → 1/3

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An=a1·q⁽ⁿ⁻¹⁾

A6=27·(1/3)⁽⁶⁻¹⁾

A6=27·(1/3)⁵

A6=27·1/243

A6=27/243 → 9/81 → 3/27 → 1/9

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(O sexto termo dessa P.G é 1/9)

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Att;Guilherme Lima