Question

resolva a equacao exponencial
$\sqrt[3]{3} {}^{x - 3} = 27$

Answer 1

$\sqrt[3]{ {3}^{x - 3} } = 27 \\ {3}^{x - 3} = {27}^{3} \\ {3}^{x - 3} = {3}^{9} \\ nesse \: caso \: sabemos \: que \: os \: expoentes \: sao \: equivalentes \\ \\ x - 3 = 9 \\ x = 9 + 3 \\ x = 12$