Question

Calcule o valor dos logaritmos: a)

log6 36 = d)

log5 0,000064 = b)

log 2 2 =

4

1

e)

=

3

log49 7

c)

=

3

log2 64 f)

log 2 0,25

Answer 1

a)
log. 36 =x
6

6^x = 36
6^x= 6^2
x = 2

B)
log 0,000064 = x
5

5^x = 0,000064
5^x= 64/10^-6
5^x = (2^6)/10^-6
5^x = (1/5)^-6
x = -6

C)
log 2 = x
2

2^x=2
X = 1

D)
log. 7=x
49

49^x =7
((7^2)^x) = 7
7^2x = 7
x = 1/2

d)
log. 64=x
2

2^x= 64
2^x=2^6
x=6

e)
log 0,25 = x
2

2^x= 0,25
2^x=(25/100)
2^x=(5/10)^2
x = 2