Question

calcule (2x-1) (2x+3)

Answer 1

(2x-1)(2x+3)=0

Primeiro aplicamos a distributiva:

4x²+6x-2x-3=0

4x²+4x-3=0

-b±√(b²-4ac)/2a

-4±√16-4*4*(-3)/8

-4±√64/8

-4±8/8

x'4/8=½

x"-12/8=-3/2

S{½,-3/2}

             Espero ter ajudado!!

Answer 2

Aplique distributiva:

(2x-1) (2x+3) ----- 4x^2 + 6x - 2x - 3

4x^2 + 4x - 3

Δ= (4)²^-4(4)(-3)

Δ=64

x = -b ± √Δ / 2a

x' = -4 + 8 / 2(4) = 1/2

x'' = - 4 - 8 / 2(4) = -3/2