Question

Equação x^2+4raiz2x+6=0

Answer 1

$x^{2} +4\sqrt2x+6=0 \\ \\ \Delta=(4\sqrt2)^2-4.1.6=8 \\ \\ x=\frac{-4\sqrt2+-\sqrt8}{2}=\frac{-4\sqrt2+-2\sqrt2}{2}=-2\sqrt2+-\sqrt2 \\ \\ x_1=-3\sqrt2 \\ \\ x_2=-\sqrt2$