Question

logx2=log2x log de x2 igual log 2 x

Answer 1

$log_2(x) = log_x(2) \\\\ log_2(x) = { log_2(2) \over log_2(x) }\\\\ log_2(x) = { 1 \over log_2(x) } \\\\\ log_2(x) \times log_2(x) = 1 \\\\ log_2(x)^2 = 1 \\\\ log_2(x) = \pm 1 \\\\ x_1 = 2 \\\\ x_2 = { 1 \over 2}$