Question

Resolva os determinantes usando a regra de cramer.
× + y + z =6
-2× + 3y + z = 7
- x + 2y + z=12

me ajudem

Answer 1

1. 1. 1 | 1. 1
-2. 3. 1 | -2. 3
-1. 2. 1 | -1. 2

( 3 - 1 - 4 ) - ( -3 + 2 -2 ) = - 2 - ( - 3 ) = -2 + 3 = 1
det= 1

det(x)

6. 1. 1| 6. 1
7. 3. 1| 7. 3
12. 2. 1| 12. 2

( 18 + 12 + 14 ) - ( 36 + 12 + 7 ) = 44 - ( 55 )= 44-55 = - 11
det(x) ÷ det(d ) = -11 ÷ 1 = -11

det(y)

1. 6. 1| 1. 6
-2. 7. 1| -2. 7
-1. 12. 1| -1. 12

( 7 - 6 - 24 ) - ( -1 + 12 - 12) = - 23 - ( - 1 ) = - 23 + 1 = - 22

det(x) ÷ det(d) = -22÷1 = -22

det(y)

1. 1. 6| 1. 1
-2. 3. 7| -2. 3
-1. 2. 12| -1. 2

( 36 + 7 - 24 ) - ( -18 + 14 - 24)= 19 - ( -28) = 19 + 28 = 47

det(z) ÷ det(d) = 47÷1= 47

S=(-11 ; -22 ; 47)