Question

equação irracionais
$\sqrt{7x - 3} - 1 = x$

Answer 1

$\sqrt{7x-3}-1=x \\ \sqrt{7x-3}=x+1 \\ (\sqrt{7x-3})^{2} = (x+1)^{2} \\ 7x-3 = x^{2}+2x+1 \\ x^{2}-5x+4=0 \\ (x-4)(x-1)=0 \\ x=4 \\ x = 1$