Question

Os segmentos AB,CD,MN e PQ formam,nesta ordem,uma proporção .Se MN =3cm,PQ cm e AB +CD =24,determine AB .

Answer 1

$mn+pq = 3 + 5 = 8\\ ab+cd = 24\\\\ raz\~ao_{_{{(mn+pq)}\rightarrow{(ab+cd)}}} = \dfrac{24}{8} = \dfrac{3}{1} = 3\\\\ ou:\\\\ raz\~ao_{_{{(ab+cd)}\rightarrow{(mn+pq)}}} = \dfrac{8}{24}=\dfrac{1}{3} \approx 0,333...$

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