Question

use o teorema de Pitágoras e determine o valor de X.

${x}^{2} = ( 2{ \sqrt{2} }{}) {}^{2} + ( \sqrt{10}) {}^{2}$

Answer 1

${x}^{2} = {2}^{2} \times 2 + 10$
${ x}^{2} = 8 + 10$
${x}^{2} = 18$
$x = \sqrt{18}$
$x = 4.242$