Question

ALGUÉM PODE ME DAR A RESPOSTA "COM CONTA ARMADA"

A)x-4=21

B)x+5=15

C)2x+8=x-4

D)6x-12=24+3x

E)2.(x+8)+10=x-12

F)5.(x-1+2(x+3)=90

G)6.(x+4)+3=8x+12

H)2x+7+3x+3=102

I)2.(x+1)+3x=17

J)5.(x+4)+20=100

Answer 1

A) X-4=21 --> X= 21+4 --> X=25

B) X+5=15 --> X=15-5 --> X=10

C) 2X+8=X-4 --> 2X-X=-4-8 --> X=-12

D) 6X-12=24+3X --> 6X-3X=24+12 --> 3X=36 --> X=36/3 --> X=12

E) 2.(X+8)+10=X-12 --> 2X+16+10=X-12 --> 2X-X=-12-16-10 --> 1X=-38 --> X=38