Question

ME AJUDEMMMMMMMMMMMMMM

Answer 1

1-C(q) = $q^{2}$-10q+500

A= 1; B= -10q; C= 500

Δ=b²-4*a*c

Δ= (-10)²-4*1*500

Δ= 100-2000

Δ= -1900

Calcularemos as vertices

$X_{v}$= $\frac{-b}{2*a}$= $\frac{-(-10)}{2*1}$= $\frac{10}{2} = 5$

$Y_{v} =$$\frac{Δ}{4*a} = \frac{-1900}{4*1}= \frac{-1900}{4}= -475$

2- Δ= b²-4*a*c

Δ= (-4)²-4*2*5

Δ=16-40

Δ= -24

$X_{v}= \frac{-b}{2*a}= \frac{-(-4)}{2*2} = \frac{4}{4}= 1$

$Y_{v}= \frac{Δ}{4*a}= \frac{-24}{4*2}= \frac{-24}{8}= -3$