Question

determine o vértice V da parábola que representa a função quadratica f(x)= -X2+3x-5

Answer 1

f(x)=-x²+3x-5

a=-1

b=3

c=-5

Δ=b²-4ac

Δ=3²-4(-1)(-5)

Δ=9+4(-5)

Δ=9-20

Δ=-11

Xv=-b/2a

Xv=-3/-2

Xv=3/2

Yv=-Δ/4a

Yv=-(-11)/4(-1)

Yv=11/-4

Yv=-11/4