Question

como resolver a equacao :
x (x + 4) + 2= 0

Answer 1

x (x + 4) + 2= 0

x^2+4x+2=0

∆=√16-4.1.2

∆=2√2

x1=-4+2√2/2

x1=-2+√2


x2=-4-2√2/2

x2=-2-√2


espero ter ajudado!

Answer 2

x² + 4x + 2 = o
∆ = 4² - 4.1.2
= 16 -8
= 8

x = - 4 ± √8 /2 => -4 ± 2√2 /2
x' = 2(-2 + √2) /2 => -2 + √2
x" = -2(2 + √2) / 2 => -2 - √2