Question

ax ao quadrado+8x+2=0

Answer 1

x²+8x+2= 0

Δ= b²-4.a.c

Δ= 8²-4.1.2

Δ= 64-8

Δ= 56    → 56= 2².14

x= -b+-√Δ/2.a

x= -8+-√(2².14)/2.1

x= -8+-2√14/2

x¹= (-8-2√14)/2

x²= (-8+2√14)/2

S= {(-8-2√14)/2  ; (-8+2√14)/2}