Question

x.(x-2)=2(x+6) me ajudeem

Answer 1

Basta fazer Bhaskara:

$x(x - 2) = 2(x + 6)\\x^2 - 2x = 2x + 12\\x^2 - 4x - 12 = 0\\a = 1\\b = -4\\c = -12\\\frac{-b\sqrt{b^2 - 4.a.c}}{2a}$

$\frac{-(-4)+-\sqrt{(-4)^2 - 4 . 1 . (-12)}}{2.1} = \\\\ \frac{ 4+-\sqrt{16 + 48}}{2}\\ \frac{ 4+-\sqrt{64}}{2}\\ \frac{ 4+- 8}{2}\\x' = \frac{4 + 8}{2} \\x' = 6\\x'' = \frac{4 - 8}{2}\\ x'' = -2$

Resposta: x' = 6 e x'' = -2