Question

x2-8x+16=0
Ajuda pfv

Answer 1

x^2-8x+16=0

x^2-8x=-16

x^2-8x+16=+16-16

(x-4)^2=0

x-4=√0

x=4

x1+x2=-b/a

x1+x2=8

x2=8-4

x2=4

s={4,4}

espero ter ajudado!

boa tarde!

Answer 2

x² - 8x + 16 = 0

A= 1
B= - 8
C= 16

∆= b² - 4ac

∆= (-8)² - 4 . 1 . 16
∆= 64 - 64
∆= 0

x= - b ± √∆ / 2a

x= - (-8) ± √0 / 2 . 1
x= 8 + 0 / 2

x'= 8 + 0 / 2 = 8 / 2 = 4
x''= 8 - 0 / 2 = 8 / 2= 4

S={ 4 }