• Matéria: Matemática
  • Autor: nathaliabtp
  • Perguntado 9 anos atrás

log x na base 2 + log 2x na base 2 + log 4x na base 2 = 6

Respostas

respondido por: Verkylen
1
\log_2(x)+\log_2(2x)+\log_2(4x)=6\\\\\log_2(x\cdot2x\cdot4x)=6\\\\\log_2(8x^3)=6\\\\8x^3=2^6\\\\(2^3)x^3=2^6\\\\x^3=\dfrac{2^6}{2^3}\\\\x^3=2^3\\\\x=2\\\\\\\boxed{S=\{2\}}
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