Question

Calcule o valor de x em cada triângulo

Answer 1

$a)\cos(60) = \frac{2 \sqrt{3} }{x} \\ \frac{1}{2} = \frac{2 \sqrt{3} }{x} \\ x = 4 \sqrt{3} \\ \\ b) \cos(60) = \frac{x}{2 \sqrt{3} } \\ \frac{1}{2} = \frac{x}{2 \sqrt{3} } \\ 2x = 2 \sqrt{3} \\ x = \frac{2 \sqrt{3} }{2} \\ x = \sqrt{3} \\ \\ c) \cos(30) = \frac{3 \sqrt{3} }{x} \\ \frac{ \sqrt{3} }{2} = \frac{3 \sqrt{3} }{x} \\ x \sqrt{3} = 6 \sqrt{3} \\ x = \frac{6 \sqrt{3} }{ \sqrt{3} } \\ x = \frac{6 \sqrt{3}. \sqrt{3} }{ \sqrt{3}. \sqrt{3} } \\ x = \frac{6 \sqrt{9} }{ \sqrt{9} } \\ x = \frac{6 \times 3}{3} \\ x = \frac{18}{3} \\ x = 6$