Question

sao dadas as expressoes;
√2^36=2^p,
t=0,0001
m=25^½.
qual e o resultado p+t+m

Answer 1

$(\sqrt{2})^{36}=2^{p} \\ 2^{ \frac{1}{2}.36}=2^{p} \\ 2^{18}=2^{p} \\ p=18$

$t =10^{-4}$

$m = 25 ^{ \frac{1}{2}} \\ m= \sqrt{25} \\ m = 5$

$p + t+m= \\ 18+0,0001+5 =\\23,0001$

ou

$p + t+m= \\ 18+10 ^{-4} +5 =\\23+10^{-4}$