Question

log(x+4) + log(x-4) - 2log3 = 0

Answer 1

$log(x+4)+log(x-4)-2log3=0 \\ log(x+4).(x-4)=2log3 \\ log(x^{2}-16)=log 3^{2} \\ log (x^{2}-16) =log9 \\ x^{2}-16 =9 \\ x^{2}-16-9=0 \\ x^{2}- 25=0 \\ x^{2} =25 \\ x= \sqrt{25} \\ \\ x'=5 \\ \\ x"=-5$