Question

calcule as potencias:

Answer 1

$(\sqrt[3]{8} \; ^{2})= (\sqrt[3]{8}\times \sqrt[3]{8})= \sqrt[3]{8\times 8}=\sqrt[3]{2^3\times 2^3}=2\times 2=4$

$(\sqrt[3]{125} )^2=(\sqrt[3]{5^3})^2 = 5^2=25$