Question

Resolva as seguinte arranjos:
a) A5, 2=
b) A7, 3=
C) A10, 7=

Answer 1

A)

A₅,₂ ⇒ 5!/(5-2)!= 5*4*3!/3!= 5*4= 20 → Resposta:)

B)

A₇,₃ ⇒ 7!/(7-3)!= 7*6*5*4!/4!= 7*6*5= 210 → Resposta:)

C)

A₁₀,₇ ⇒ 10!/(10-7)! = 10*9*8*7!/3!= 10*9*8*7*5*4*3!/3!= 10*9*8*7*6*5*4= 604800 → Resposta:)

Answer 2

Boa noite!

a) A(5, 2)

A(n,p)=n!/(n-p)!

A(5, 2)=5!/(5-2)!

A(5, 2)=5!/3!

A(5, 2)→5×4×3!/3!

A(5, 2)→5×4 = 20

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b) A(7, 3)

A(n,p)=n!/(n-p)!

A(7, 3)=7!/(7-3)!

A(7, 3)=7!/4!

A(7, 3)→7×6×5×4!/4!

A(7, 3)→7×6×5=210

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C) A(10, 7)

A(n,p)=n!/(n-p)!

A(10, 7)=10!/(10-7)!

A(10, 7)=10!/3!

A(10, 7)=10×9×8×7×6×5×4×3!/3!

A(10, 7)→10×9×8×7×6×5×4 = 604800

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Att;Guilherme Lima