Question

resolva:
log x 1/7=-1

Answer 1

Oi!

Propriedade
$\boxed{log_b(a) = x <=> b^x = a}$

$log_x(\frac{1}{7}) = - 1 \\ {x}^{- 1} = \frac{1}{7} \\ {x}^{- 1} = {7}^{- 1} \\ \boxed{x = 7}$
Bons estudos!