Question

Me ajudem!
a) 1

b) – 11
      6

c) 2

d) – 5
     2

e) 7
   4

Answer 1

$Resolu\c{c}\~ao \to  \left\{\begin{array}{ccc}\frac{2^{98} + 4^{50} - 8^{34}}{2^{99}-32^{20}+2^{101}} = \\\\\frac{2^{98} + 2^{100} - 2^{102}}{2^{99} - 2^{100} + 2^{101}} = \\\\ \frac{2^{98}*(1 + 2^{2} - 2^{4})}{2^{98}*(2^{1} - 2^{2} + 2^{3})} = \\\\\frac{1+4-16}{2-4+8} = \\\\\boxed{\boxed{\frac{-11}{6}}}\end{array}\right$

Espero ter ajudado! =^.^=