Question

considerando log2 0,3010 e log3 0,4771 calcule log 30

Answer 1

$= log(30) \\ = log(4 \times 5) \\ = log( {2}^{2} \times 5 ) \\ = log( {2}^{2} ) + log(5) \\ = 2 log(2) + log(5) \\ = 2(0.3010) + 0.4771 \\ = 0.6020 + 0.4771 \\ = 1.0791$