Question

Dada a funçao f(x)= 3x²-7x+3 determine
@
A) f(0)
B) f(-1)
C) f(⅓)
D)(√2

Answer 1

f(0)= 3.0²-7.0+3=0-0+3=3

f(-1)=

3.(-1)²-7(-1)+3=

3.1+7+3=

3+7+3=

13

f(1/3)=

3.(1/3)²-7(1/3)+3=

3.1/9-7/3+3=

3/9-7/3+3=

1/3-7/3+3=

-6/3+3=

-2+3=

1

f(V2)=

3(V2)²-7(V2)+3=

3.2-7V2+3=

6-7V2+3=

9-7V2