• Matéria: Matemática
  • Autor: saci42
  • Perguntado 7 anos atrás

1) RESOLVA AS FUNÇÕES EXPONENCIAIS

A) 2^{3X-2} + 64^{X+2}

B) 7^{X+3} = 49^{2(X-3)}

Respostas

respondido por: Fabionps
1

a)\\2^{3x-2}=64^{x+2}\\2^{3x-2}=(2^{6})^{x+2}\\2^{3x-2}=2^{6x+12}\\\\3x-2=6x+12\\3x-6x=12+2\\-3x=14\\x=-\frac{14}{3} \\\\\\b)\\\\7^{x+3}=49^{2(x-3)}\\7^{x+3}=(7^{2})^{2(x-3)}\\7^{x+3}=7^{4(x-3)}\\7^{x+3}=7^{4x-12}\\\\x+3=4x-12\\x-4x=-12-3\\-3x=-15\\x=5\\\\\\


Espero ter ajudado :)

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