Question

como resolver essa conta : efetue √125+2√27-√20+3√12

Answer 1

raiz 125 = $\sqrt{5^2*5}$

raiz 27 = $\sqrt{3^2*3}$

raiz de 20 = $\sqrt{2^2*5}$

raiz 12 = $\sqrt{2^2*3}$

$5 \sqrt{5} + 2*3 \sqrt{3} -2 \sqrt{5}+3*2 \sqrt{3} \\ \\ 5 \sqrt{5}+6 \sqrt{3}-2 \sqrt{5}+6 \sqrt{3} \\ \\ 3 \sqrt{5} + 12 \sqrt{3}$

BONS ESTUDOS!

Answer 2

√125 = 5 √5
2√27 = 6√3
√20 = 2√5
3√12 = 6√3
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5√5+6√3-2√5+6√3 = 3√5+ 12√3