Question

matemática galera assunto números complexos ajuda aí

Answer 1

2 - a) 20 : 4 = 5 (resto 0)

i⁰ = 1

3z + 4i = z - 6*(1)

3z - z = - 6 - 4i

2z = - 6 - 4i

z = - 6/2 - 4i/2

z = - 3 - 2i

b) 3zi = z + 1

3zi - z = 1

z( 3i - 1 ) = 1

z = 1 / 3i - 1

z = 3i - 1 / (3i - 1)(3i - 1)

z = 3i - 1 / 10

3 - a) i⁹

9 : 4 = 2  (resto 1)

i¹ = i

i⁹ = i

b) i¹⁴

14 : 4 = 3 (resto 2)

i² = - 1

i¹⁴ = - 1

c) i⁶⁰

60 : 4 = 15 (resto 0)

i⁰ = 1

i⁶⁰ = 1

d) i⁹⁹

99 : 4 =  24 (resto 3)

i³ = -i

i⁹⁹ = -i

e) i¹⁰³⁵

1035 : 4 = 258 (resto 3)

i³ = -i

i¹⁰³⁵ = -i

e) (-i)¹⁶

(+i)⁰ = 1