Question

Equação exponencial:
${2}^{4x + 1} \times {8}^{ - x + 3} = \frac{1}{16}$

Answer 1

$2 {}^{4x - 1} \times 8 {}^{ - x + 3} = \frac{1}{16} \\ 2 {}^{4x - 1 } \times 2 {}^{3( - x + 3)} = ( \frac{1}{2} ) {}^{4} \\ 2 {}^{4x - 1 + 3( - x + 3)} = 2 {}^{ - 4} \\ 4x - 1 - 3x + 9 = - 4 \\ 4x - 3x = - 9 + 1 - 4 \\ x = - 12$