Question

quais sao as raizes da equaçao(x+3)²=16?

Answer 1

(x+3)^2 = 16

x^2 +6x + 9 = 16
x^2 + 6x + 9 - 16 = 0
x^2 + 6x - 7 = 0
Delta = b^2 - 4.a.c
Delta = 36 - 4.(1)(-7)
Delta = 36 + 28
Delta = 64

X1 = (-b + raiz_quadrada(Delta))/2a
X1 = (-6 + 8)/2 = 1

X2 = (-b - raiz_quadrada(Delta))/2a
X2 = (-6 - 8)/2 = -14/2 = -7

Espero ter ajudado.