Question

Determine as raízes das equações X2+12×=28

Answer 1

x²+12×=28

x²+12x-28=0

Δ=(-12)²-1.4.(-28)

Δ=144+112

Δ=256

• -12 +/-√256/2.1
• -12+16/2→ 4/2→ 2
• -12-16/2→ -28/2 → -14
• x(2,-14)

Answer 2

OI

x² + 12x = 28

x² + 12x - 28 = 0

Coeficientes:

a = 1

b = 12

c = - 28

Calculando delta

Δ = b² - 4.a.c

Δ = 12² - 4 .1.-28

Δ = 144 + 112

Δ = 256

Há 2 raízes reais.

x = - b +- √Δ/2.a

x' = - 12 + √256/2.1

x' = - 12 + 16/2

x' = 4/2

x' = 2

x" = - 12 - √256/2.1

x" = - 12 - 16/2

x" = - 28/2

x" = - 14

S = {x' = 7 e x" = - 14}

Espero ter ajudado.