Question

resolver usando a formula de bhaskara ? 4y²-5y-21=0

Answer 1

resolver usando a formula de Bháskara ?

4y² - 5y - 21 = 0

delta

d² = 25 + 4*4*21 = 361

d = 19

y1 = (5 + 19)/8 = 24/8 = 3

y2 = (5 - 19)/8 = -14/8 = -7/4

Answer 2

Vamos lá

Calculo:

4Y² - 5Y - 21 = 0

Os coeficientes

A = 4

B = - 5

C = - 21

Calculando delta

Δ = b² - 4 • a • c

Δ = ( - 5 )² - 4 • 4 • ( - 21 )

Δ = 25 + 336

Δ = 361

Aplicando bhaskara

Y = - b ± √Δ / 2 • a

Y = 5 ± √ 361 / 2 • 4

Y = 5 ± 19 / 8

Y1 = 5 + 19 / 8 = 24 / 8 = 3

Y2 = 5 - 19 / 8 = - 14 / 8 = - 7 / 4

S { 3 , - 14 / 8 }