Question

Se log 2=0,301;log 3=0,477 e log 5=0,6999 calcule:
a) log 216=
b) log 2500=
c) log 60=

Answer 1

a) log 216= log (2.2.2.3.3.3) = 3. Log 2 + 3. Log 3 = 3. 0,301 + 3. 0,477 = 0,903 + 1,431 = 2,334
b) log 2500 = (5.5.5.5.2.2) = 4 log 5 + 2 log 2 = 2,7996 + 0,602 = 3,4016
c) log 60 = log (3.2.2.5) = log 3 + log 5 + 2 log 2 = 0,477 + 0,6999 + 0,602 = 1,7789