Question

Interpole 5 meios geometricos entre 3/4 e 48

Answer 1

an=48

a1=3/4

an=a1.q^n-1

3/4.q^7-1=48

3/4.q^6=48

q^6=48÷3/4

q^6=48×4/3

q^6=192/3

q^6=64

(q)^6=(2)^6

q=2

PG{3/4;6/4;3;6;12;24;48}


espero ter ajudado!

boa tarde!