Question

Dados Log 2 =0,301,Log 3 = 0,505 e Log 5= 0,699,determine

A) Log 20
B)Log 50
C) Log 90
D) Log 0,9
E) Log 0,6
F)Log0.8 ÷

Answer 1

Log 2 =0,301 , Log 3 = 0,505 e Log 5= 0,699

A) log 20 = log 4.5 = log 4+log 5= 2log 2 + log 5= 2(0,301)+0,699=1,301

B) log 50 = log 25.2 = log 5²+log 2= 2log 5 + log 2=2(0,699)+0,301=1,699

C) log 90 = log 9.5.2 = log 3²+log 5 +log 2= 2log 3 + log 5 +log 2= 2(0,505)+0,699+0,301=2,01

D)  log 0,9 = log 9/10 = log 3²-(log 5 +log 2)= 2log 3 - log 5 -log 2= 2(0,505)-0,699-0,301=0,01

E)  log 0,6 = log 6/10 =log 3/5 =  log 3-log 5 = 0,505-0,699= -0,194

F) log 0,8 = log 8/10 =log 4/5 =  log 2²-log 5 = 2(0,301) - 0,699= -0,097