Question

b^-4ac=para a=3,b=8,c=4

Answer 1

Vamos lá:

$\Delta = b^{2} -4*a*c \\ \\ \Delta = 8^2 -4*3*4\\\\\Delta = 64 -48\\\\\Delta = 16$

Valores de x:

$x' = \frac{-8+ \sqrt{16} } {2*3} \\\\x'= \frac{-8+4 }{6}\\ \\x'= \frac{-4}{6} :2\\\\\boxed{x' = \frac{-2}{3}} \\\\--------------------\\\\x" = \frac{-8- \sqrt{16} } {2*3}\\ \\x" = \frac{-8-4}{6}\\ \\x" = \frac{-12}{6}\\ \\\boxed{x" = -2} \logo,\\ \\\boxed{S =(- \frac{2}{3} ; -2)}$

Bons estudos !