Question

valor de x que satisfaz 3³×-¹.9²×+³ = 27³-× é:

Answer 1

$3^{3x-1}\cdot9^{2x+3}=27^{3-x}\\ \\3^{3x-1}\cdot3^{2\cdot(2x+3)}=3^{3\cdot(3-x)}\\ \\3^{3x-1}\cdot3^{4x+6}=3^{9-3x}\\ \\3^{3x-1+(4x+6)}=3^{9-3x}\\ \\3^{7x+5}=3^{9-3x}$

Igualando os expoentes:

$7x+5=9-3x\\ \\7x+3x=9-5\\ \\10x=4\\ \\x=\frac{4}{10}=\frac{2}{5}$