Question

simplificando a expressão 2^n.4 obtem-se ?
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8 ^ 1/3. 2 ^3n+1

Answer 1

$\frac{2^{n} \cdot 2^{2}}{\sqrt[3]{2^{3}} \cdot 2^{3n +1}}\\\\\frac{2^{n} \cdot 2^2}{2^{3n} \cdot 2 \cdot 2} \\\\\frac{2^{n}}{2^{3n} }\\\\2^{-2n}$