Question

calcule o zero da função: f(x)=18x²-3x-1

Answer 1

f(x)=18x²-3x-1

para f(x)=0

18x^2-3x-1=0

∆=b^2-4.a.c

∆=(-3)^2-4.18.(-1)

∆=9+72

∆=81

X1=-b+√∆/2.a

X1=-(-3)+√81/2.18

X1=3+9/36

X1=12/36

X1=2/6

X1=1/3

X2=-b-√∆/2.a

X2=-(-3)-√81/2.18

X2=3-9/2.18

X2=2.(-3)/2.18

X2=-3/18

X2=-1/6

s={1/3;-1/6}


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