Question

o valor da integral definida 0 e -3 (2x elevado a 4-8x elevado3+14x^2)dx/2x^2

Answer 1

$\int\limits^0_{-3} {\frac{2x^4-8x^3+14x^2}{2x^2}} \, dx \\\\Divididndo\;o\;numerador\;e\;denominador\;por\;2x^2:\\\\\int\limits^0_{-3} {x^2-4x+7} \, dx \\\\\left(\frac{x^3}{3}-\frac{-4x^2}{2}+7x\right|_{-3}^0\\\\\left(\frac{0^3}{3}-\frac{0}{2}+0\right)-\left(\frac{(-3)^3}{3}+\frac{-4.(-3)^2}{2}+7.(-3)\right)\\\\0-\left(-9-18-21\right)\\\\-(48)\\\\48$