Question

dada a função
determine os valores de x para os quais y=0
$y = {x}^{2} - 5x + 6$

Answer 1

xy+{4}^{5}=39gugugugugufhc

Answer 2

x^2-5x+6=0
∆=(-5)^2-4.1.6
∆=25-24
∆=1
x=-6+ou-√1/2
x=-6+1/2. x=-5/2
x=-6-1/2. x=-7/2