Question

se 
${10}^{x} = {20}^{y}$

atribuindo 0.3 para log 2, então o valor de x/y é:

Answer 1

10^x=20^x

log20 = log(2.10) = log10+log2 = 1+0,3 = 1,3

(10)^x=(10)^1,3y

x=1,3y

y=x/1,3

x/y=1,3y ÷ x/1,3


x/y=13/10y÷x/13

x/y=169/10xy

x/y=169/10xy