Question

Galera alguém consegue fazer a 16 aí PF...valeu

Answer 1

$a)\\\frac{\frac{1}{3}}{\frac{2}{5}}\;=\;\frac{1}{3}.\frac{5}{2}\;=\;\frac{5}{6} \\\\b)\\\frac{\frac{7}{1}}{\frac{2}{3}} \;=\;\frac{7}{1}.\frac{3}{2}\;=\;\frac{21}{2} \\\\c)\\\frac{\frac{5}{7}}{\frac{6}{1}} \;=\;\frac{5}{7}.\frac{1}{6}\;=\;\frac{5}{42} \\\\d)\\\frac{\frac{3}{4}}{\frac{7}{3}} \;=\;\frac{3}{4}.\frac{3}{7}\;=\;\frac{9}{28} \\\\e)\\\frac{\frac{9}{1}}{1\frac{1}{4}} \;=\;\frac{9}{1}.\frac{4}{1.4+1}\;=\;\frac{9}{1}.\frac{4}{5}\;=\;\frac{36}{5}$

$f)\\\frac{1\frac{1}{3}}{\frac{5}{1}} \;=\;\frac{3.1+1}{3}.\frac{1}{5}\;=\;\frac{4}{3}.\frac{1}{5}\;=\;\frac{4}{15}$

$g)\\\frac{\frac{6}{5}}{\frac{1}{2}+\frac{1}{3}} \;=\;\frac{6}{5}.\frac{6}{3.1 + 2.1}\;=\;\frac{6}{5}.\frac{6}{5}\;=\;\frac{36}{25}\\\\h)\\\frac{1+\frac{3}{4}}{2-\frac{1}{2}} \;=\;\frac{1.4+3}{4}.\frac{2}{2.2-1}\;=\;\frac{7}{4}.\frac{2}{3}\;=\;\frac{14}{12}=\frac{7}{6}$