Question

Me ajudem!

(x²-4x+3).(x²+4x)

Answer 1

(x² - 4x + 3) . (x² + 4x)

Aplicando a distributiva:

x².x² + x² . 4x - 4x . x² - 4x . 4x + 3 . x² + 3 . 4x

$x^4+4x^3-4x^3-16x^2+3x^2+12x$

$x^4-13x^2+12x$

Answer 2

(x² - 4x + 3)(x² + 4x)

x⁴ + 4x³ - 4x³ - 16x² + 3x² + 12x

x⁴ - 13x² + 12x